Last week I think I tripped a few of you up…Congrats to still unreal for getting the right answers.

sin θ = Opposite over Hypotenuse = Y/X

cos θ = Adjacent over Hypotenuse = Z/X

tan θ = Opposite over Adjacent = Y/Z

csc θ = 1/Opposite over Hypotenuse = 1/(Y/X) = X/Y

sec θ = 1/Adjacent over Hypotenuse = 1/(Z/X) = X/Z

cot θ = 1/Opposite over Adjacent = 1/(Y/Z) = Z/Y

This week we will use the same “lopsided” triangle and solve for Z (and before someone points it out) the triangle is NOT to scale!


5 comments so far

  1. still Unreal... on

    How would you like this to be part of your entry in Wiki? lol

    Main interests: Metaphysics, Music, Mathematics, Ethics, Politics
    Notable ideas: Musica universalis, Golden ratio, Pythagorean tuning, Pythagorean theorem
    Influences: Thales, Anaximander, Pherecydes
    Influenced: Philolaus, Alcmaeon, Parmenides, Plato, Euclid, Empedocles, Hippasus, Kepler


  2. steveegg on

    Wiki? Bah, humbug.

    SU – you forgot to show your work (which was a major fault of mine; I almost never did either).

    Given the Pythagorean Theorem, in which the sides a and b and hypotenuse c of a right triangle are related with the formula a^2 + b^2 = c^2, set a to 12, b to Z and c to 13, and solve thusly:

    12^2 + Z^2 = 13^2
    Z^2 = 169 – 144
    (Z^2)^.5 = (25)^.5
    Z = 5

    And I’ll take the bonus for not using a calculator 🙂

  3. still Unreal... on

    Oh, yeah?
    I get a bonus for the quick look up of Mr. Pythagoras, too.

    Show my work???
    How do you not know the Pythagorean Theorem??

  4. gopfolk on

    My wife did the math in her head and talked the whole thing out…now that is bonus points!


    steveegg…thanks for showing your work!


  5. still Unreal... on

    That’s crap!
    I want a “check+”!
    (see: south park)

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