### Math

Last week I think I tripped a few of you up…Congrats to still unreal for getting the right answers.

**sin θ** = Opposite over Hypotenuse = **Y/X**

**cos θ** = Adjacent over Hypotenuse = **Z/X**

**tan θ** = Opposite over Adjacent = **Y/Z**

**csc θ** = 1/Opposite over Hypotenuse = 1/(Y/X) = **X/Y**

**sec θ** = 1/Adjacent over Hypotenuse = 1/(Z/X) = **X/Z**

**cot θ** = 1/Opposite over Adjacent = 1/(Y/Z) = **Z/Y**

This week we will use the same *“lopsided”* triangle and **solve for Z** (and before someone points it out) the triangle is NOT to scale!

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How would you like

thisto be part of your entry in Wiki? lolMain interests:Metaphysics, Music, Mathematics, Ethics, PoliticsNotable ideas:Musica universalis, Golden ratio, Pythagorean tuning, Pythagorean theoremInfluences:Thales, Anaximander, PherecydesInfluenced:Philolaus, Alcmaeon, Parmenides, Plato, Euclid, Empedocles, Hippasus, KeplerWhoa.

5?

Wiki? Bah, humbug.

SU – you forgot to show your work (which was a major fault of mine; I almost never did either).

Given the Pythagorean Theorem, in which the sides

aandband hypotenusecof a right triangle are related with the formulaa^2 + b^2 = c^2, setato 12,bto Z andcto 13, and solve thusly:12^2 + Z^2 = 13^2

Z^2 = 169 – 144

(Z^2)^.5 = (25)^.5

Z = 5And I’ll take the bonus for not using a calculator 🙂

Oh, yeah?

I get a bonus for the quick look up of Mr. Pythagoras, too.

Show my work???

How do you not know the Pythagorean Theorem??

My wife did the math in her head and talked the whole thing out…now that is bonus points!

🙂

steveegg…thanks for showing your work!

😉

That’s crap!

I want a “check+”!

(see: south park)